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Tuesday, February 26, 2013

Bioe339 Hw 8#4 Ans

dose 1.3 1.3 1.3 1.3 4.5 4.5 4.5 4.5 13.5 13.5 13.5 13.5

Negative

Positive

73.61 130.69 118.01 140.2 26.95 53.23 59.57 53.23 -8.83 25.14 20.16 34.65

170.72 85.36 244.95 122.475 238.27 119.135 232.59 116.295 55.46 27.73 83.88 41.94 103.94 51.97 89.46 44.73 -44.63 -22.315 17.21 8.605 1.08 0.54 40.01 20.005 726.61 506.33 original 60.55083 42.19417 Mean 1232.94 51.3725 SST 494.4842 6291.186 4440.49 7890.236 596.4829 3.448449 67.19081 3.448449 3624.401 688.1703 974.2514 279.6587

97.11 114.26 120.26 92.39 28.51 30.65 44.37 36.23 -35.8 -7.93 -19.08 5.36

Dose 1 Dose 2 Dose 3 Sum

Total Mean 886.53 110.8163 332.74 41.5925 13.67 1.70875 1232.94 SSA =

SSB =

Total Total mean

(Xi-Xbar)^2 2091.873 3954.775 4745.419 1682.394 522.7168 429.4427 49.04201 229.3104 7599.132 3516.846 4963.625 2117.196 Sum 57255.221 SST

1011.269 1011.269 2022.538

SSAB=

19.08816 6.375625 47.61 19.0445 6.4009 47.3344 145.

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Assumption Normally distributed universe of discourse and has same variance Random sample of size 4 Hypothesis H0: Ai =0 for I = 1, 2, 3…a HA: all Ai are not friction match to 0 H0: Bi =0 for I = 1, 2, 3…b HA: all Bi are not pertain to 0 singular level of neuroprotection find different levels of neuroprotection detected singularity detected different levels detected

Test Statictic V.R. (A)= MSA/ MSE V.R.(B) = MSB/ MSE dissemination of Test Statictic (A) df in numerator is 2 and denominator 6 (B) df in numerator is 1 and denominator 6 decision rule alpha=0.05 F1 =5.14 F2 =5.99 Calculation of quiz Statictic ANOVA Source A interrupt B Block AB Block Treatment Residue Total

SS SSA SSB SSAB SSTr SSE SST

df 2 1 2 1 6 7

SS 48765.57 2022.538 145.8536 50933.96 6321.262 57255.22

MS VR 24382.78 7.7145299 2022.538 0.3199579 72.92679 50933.96 1053.544 8179.317

statistical Decision 7.714 >5.14 Therefore the first NULL hypothesis hindquarters be rejected 0.3199If you want to get a bounteous essay, order it on our website: Ordercustompaper.com



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